text{Phthalic anhydride} xrightarrow {PCl_5} | vedclass

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(A) $1$. Phthalic anhydride reacts with $PCl_5$ to form phthaloyl chloride $(A)$.$2$. Phthaloyl chloride is reduced by $LiAlH_4$ to form benzene$-1,2-

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(A) $1$. Phthalic anhydride reacts with $PCl_5$ to form phthaloyl chloride $(A)$.$2$. Phthaloyl chloride is reduced by $LiAlH_4$ to form benzene$-1,2-$dimethanol $(B)$.$3$. Benzene$-1,2-$dimethanol is oxidized by $PCC$ to form phthalaldehyde $(C)$.$4$. Phthalaldehyde undergoes an intramolecular Cannizzaro reaction in the presence of $OH^-$ and $\Delta$ to form the phthalide anion,which is the salt of $2-$(hydroxymethyl)benzoic acid $(D)$.

$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$
Compound $D$ is :-

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$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$ Compound $D$ is :-